If nondisjunction occurs in meiosis ii, how many of the four gametes will be aneuploid?.

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04-11-2022
Biology

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If nondisjunction occurs in meiosis ii, how many of the four gametes will be aneuploid?.

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qwoffwhite qwoffwhite · Answer 1 · 2022-11-07T08:32:48-05:00

If nondisjunction occurs in meiosis ii, two of the four gametes formed will be aneuploid.

Sister chromatids cannot split during anaphase II, which leads to nondisjunction in meiosis II. Two of the four daughter cells will have a typical complement of 23 chromosomes since meiosis went off without a hitch. One of the other two daughter cells, which will have n+1 and n-1, will be aneuploid. Two of the four products will be unharmed by the event, and two will be aberrant if nondisjunction occurs in meiosis II.

Chromosome non-disjunction during mitosis or meiosis is the most frequent cause of aneuploidy. Anaphase is the time of mitotic non-disjunction of chromosomes. The two daughter cells produced when a somatic cell divides but doesn't suffer disjunction are aneuploid.

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