3476.39 KJ, heat is required to boil 250.1 g of water .
In the given question we have following information,
As we know that,
Molar mass of water = 18.0 g/mol
Now, firstly we convert the mass of water to moles by using molar mass ,
moles of water = mass of water / molar mass of water
moles of water = 250.1 g/18.0 g/mol = 13.89moles = 13.9 moles of water
We can find out required heat to 250.1 g of water by using the heat of vaporization or enthalpy for boliling water.
Required heat to boil 250.1 g of water = 13.9 moles of water × 40.7 KJ/mole of water = 3476.39KJ
To learn more about heat , refer:
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