The voltage across the capacitor, which is 3V, will represent the emf of the battery.
The energy provided by a battery or cell per coulomb (Q) of charge travelling through it is known as the (EMF), or electromotive force. When there is no current flowing through the circuit, the emf across the cell terminals has a magnitude equal to V (potential difference).
We are given that,
The amount of charge = Q = 30μC
The capacitance = C = 10μC
Thus, to compute the voltage (V) across a capacitor by the formula,
V = Q/C
V =30/10
V = 3volts
Therefore ,the voltage across a 10μF capacitor will be 3V if a switch that connects a battery to it is closed for a few seconds and the capacitor plates are heated to 30μC.
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