when the sledder slides to the top of the left hill (shown in the figure below), her speed is 6.5 m/s. the total mass of the girl and the sled is 55 kg. she continues sliding down, passes the valley and moves up on the right hill. what is the speed of the sledder at the top of the right hill assuming a thermal energy of 160 j is generated due to friction during the sliding process?

Question

04-11-2022
Physics

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when the sledder slides to the top of the left hill (shown in the figure below), her speed is 6.5 m/s. the total mass of the girl and the sled is 55 kg. she continues sliding down, passes the valley and moves up on the right hill. what is the speed of the sledder at the top of the right hill assuming a thermal energy of 160 j is generated due to friction during the sliding process?

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AnnuG AnnuG · Answer 1 · 2022-11-09T11:32:06-05:00

The speed of the sledder at the top of the right hill assuming a thermal energy of 160 j is generated due to friction during the sliding process is 1.8 m / s

According to law of conservation of energy,

m1 g h1 + 1 / 2 m1 v1² = m2 g h2 + 1 / 2 m2 v2²

m1 = m2 = m

m g h1 + 1 / 2 m v1² = m g h2 + 1 / 2 m v2² - W

W is included because there is some energy lost as heat.

g = 9.8 m / s²

h1 = 4.2 m

v1 = 6.5 m / s

h2 = 5.9 m

H = 160 J

m = 55 kg

g h1 + 1 / 2 v1² = g h2 + 1 / 2 v2² + W / m

( 9.8 * 4.2 ) + ( 1 / 2 * 6.5² ) = ( 9.8 * 5.9 ) + ( 1 / 2 * v2² ) + ( 160 / 55 )

41.16 + 21.13 = 57.82 + v2² / 2 + 2.91

v2² = 1.56 * 2

v2 = 1.8 m / s

Therefore, the speed of the sledder is 1.8 m / s

To know more about law of conservation of energy

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