Answered

one capacitor is charged until its stored energy is 6.0 j. a second uncharged capac- itor is then connected to it in parallel. (a) if the charge distributes equally, what is now the total energy stored in the electric fields? (b) where did the excess energy go?



Answer :

The total energy stored in the electric field is 13 J.

Let the capacitance of the capacitor be C

Then we have for a charged stored Q, the energy equal to

E = - 6 2C

Now, a capacitor of the same capacitance is connected in parallel

So, the charge on each will become half i.e., Q/2

So, total energy becomes

1 (*) E = 2 x 2C = Q? 4C = X 2C x 6 J=13 J

b) The excess energy might have been emitted as heat and some of it has been radiated

A capacitor is a tool that stores electric electricity in an electric-powered area by way of virtue of amassing electric prices on two near surfaces insulated from every difference. it is a passive digital element with two terminals. The effect of a capacitor is referred to as capacitance.

Capacitor is a tool for storing electrical strength, inclusive of conductors in close proximity and insulated from each other. An easy instance of this sort of storage tool is the parallel-plate capacitor. the principle characteristic of capacitors is to save electrostatic strength in an electric-powered discipline, and deliver this electricity to the circuit, when vital. They permit the AC to pass but block the glide of DC to keep away from an unsafe breakdown of the circuit.

Learn more about capacitors here:-https://brainly.com/question/13578522

#SPJ4

Other Questions