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A 57. 0-g tennis ball is traveling straight at a player at 21. 0 m/s. The player volleys the ball straight back at 25. 0 m/s. If the ball remains in contact with the racket for 0. 060 s, what average force acts on the ball?.



Answer :

According to the given statement is 43.7 N average force acts on the ball.

What is the average force ?

The average force is a force applied by an object travelling more than a specific period of time at a given rate of speed, or velocity. This velocity is not instantaneous or accurately measured, as the word "average" implies.

Briefing:

Mass of tennis ball is =57 gm

velocity of ball=21 m/s

At a speed of 25 m/s, the player volleys the ball back (i.e. in opposite of initial direction)

Time of contact=0.06 s

We know change in momentum(ΔP)  = Impulse (Fdt)

Initial momentum = 57 * 10⁻³ * 21

Final momentum = -57 * 10⁻³ * 25

Change in momentum

ΔP = 57 * 10⁻³ * 21 - (-57 * 10-3 * 25)

ΔP =  57 * 10⁻³ * 46 = 2.622 kg-m/s

Now 2.622 kg-m/s = F[tex]_a_v_g[/tex] * 0.06

F[tex]_a_v_g[/tex] = 43.7 N

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