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a charged particle of mass 0.0020 kg is subjected to a magnetic field which acts at a right angle to its motion. if the particle moves in a circle of radius at a speed of what is the magnitude of the charge on the particle? a) 0.0083 c b) 120 c c) 0.00040 c d) 2500 c



Answer :

The magnitude of the charge on the particle of mass 0.0020 kg that is subjected to a magnetic field of 6 T which acts at a right angle to its motion is 0.0083 C ( a )

Fm = q v B

Fc = m v² / r

Fm = Magnetic force

q = Charge of the particle

v = Velocity of the particle

B = Magnetic field strength

Fc = Centripetal force

m = Mass

v = Velocity

r = Radius

m = 0.002 kg

v = 5 m / s

r = 0.2 m

B = 6 T

Since the magnetic force causes the centripetal motion,

q v B = m v² / r

q = m v / B r

q = 0.002 * 5 / 6 * 0.2

q = 0.01 / 1.2

q = 0.0083 C

Therefore, the magnitude of the charge on the particle is 0.0083 C ( a )

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