A sample of 2.0 L of oxygen at 3.0 atm pressure if the pressure to 5.0 atm . the volume is 1.2 L.
Given that :
the volume of oxygen , V1 = 2.0 L
the pressure of oxygen , P1 = 3.0 atm
the pressure P2 = 5.0 atm
volume V2 = ?
According to Boyles law :
P1V1 = P2V2
3 × 2 = 5 × V2
6 = 5V2
V2 = 6/5
V2= 1.2 L
Thus, A sample of 2.0 L of oxygen at 3.0 atm pressure if the pressure to 5.0 atm . the volume is 1.2 L.
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