two children of mass 21 kg and 33 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. if the children are separated by a distance of 5 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?



Answer :

The distance from the pivot point from which the small child sitting in order to maintain the balance is 3.1 m

In equilibrium,

Clockwise moment = Anticlockwise moment

Let the distance of small child from the pivot point be x. So the distance of large child from the pivot point would be 5 - x

33 ( 5 - x ) = 21 x

165 - 33 x = 21 x

54 x = 165

x = 3.1 m

If the effect of the body is turn in anticlockwise direction, the moment force is called anticlockwise moment and is taken positive. If the effect of the body is turn in clockwise direction, the moment force is called clockwise moment and is taken negative.

Therefore, the distance from the pivot point from which the small child sitting in order to maintain the balance is 3.1 m

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