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what is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wavelength of 455 nmnm ? the index of refraction of the film is 1.35, and there is air on both sides of the film. express your answer in nanometers.



Answer :

The thinnest soap film that appears black when illuminated with light with a wavelength of 455 nm is 168.52 Nm

For thinnest soap film,

2 t = λ / n

t = Thickness

λ = Wavelength

n = Refractive index

λ = 455 Nm

n = 1.35

t = 455 / 2 * 1.35

t = 168.52 Nm

Refractive index is the light bending ability of any medium that can bend light. It describes the amount of light refracted when entering the medium.

n = c / v

c = Speed of light

v = Phase velocity of light

Therefore, the thinnest soap film that appears black is 168.52 Nm

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