Answered

if it takes 20.0 ml of 0.050 m h2so4 (aq) to neutralize (reach equivalence point) 8.00 ml of an unknown concentration of lioh(aq), what is the concentration of the lioh? show your work.



Answer :

The magnitude of the concentration that LiOH(aq) employs to neutralize the reaction is 0.125 M.

What is the concentration of LiOH(aq)?

[tex]M__{H_{2}SO_4 }[/tex] = M₁ = 0,050 M

[tex]V__{H_{2}SO_4 }[/tex] = V₁  = 20,0 ml

[tex]V__{LiOH }[/tex] = V₂ = 8,00 ml

Thus, solving for the final morality is:

M₁V₁ = M₂V₂

M₂ = [tex]\frac{M_1V_1}{V_{2}}[/tex]

So, plugging in the values we obtain:

M₂ =  [tex]\frac{0,050x20,0}{8,00}[/tex]

M₂ = 1 : 8,00

M₂ = 0,125 M

Then the magnitude of the concentration that LiOH employs to neutralize the reaction is 0.125 M.

Learn more about calculating the concentration of the solution at https://brainly.com/question/19091247

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