In given question both cars have same friction but radius of curvature for car B is more that of radius of curvature of car A. So centrifugal force on B is less that acting on A , because Fcf= Mv² / r, ra is less than rb . So correct choice is E.
The main cause of sliding is centrifugal force when car take turn, this centrifugal force is balanced by centripetal force provided by friction between road and tires.
When a car takes a turn, the tires experience a force known as the centrifugal force. This force is caused by the car's momentum as it moves around the turn. The centrifugal force is opposed by the centripetal force, which is provided by the friction between the road and the tires.
Both cars have the same amount of friction. However, the radius of curvature for car B is greater than the radius of curvature for car A. This means that the centrifugal force on car B is less than the centrifugal force on car A. The reason for this is that the centrifugal force is directly proportional to the car's mass and the square of its velocity. Since car B has a greater radius of curvature, it experiences less of a centrifugal force.
Learn more about centrifugal force at : https://brainly.com/question/17167298
#SPJ4
Complete Question.
Multiple choice question.
A. The two cars are equally likely to slide off the road because their masses are equal.
B. The two cars are equally likely to slide off the road because their speeds are equal.
C. Car B because it is closer to the outer side of the turn.
D. Car B because the distance it travels around the turn is larger.
E. Car A because it moves through the turn with a smaller radius.
F. Car A because the distance it travels around the turn is smaller.
