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the figure below displays a circular loop of nickel wire in a uniform magnetic field pointing into the page. the radius of the loop is 15.0 cm and the magnitude of the field is 0.170 t. you grab points a and b and pull them in opposite directions, stretching the loop until its area is nearly zero, taking a time of 0.150 s to do so. what is the magnitude of the average induced emf in the loop (in mv) during this time?



Answer :

onyebuchinnaji

The magnitude of the average induced emf in the loop (in mv) during this time is 80.5 mV.

What is the magnitude of the emf induced?

The magnitude of the emf induced in the coil is calculated by applying the following equation as shown below;

emf = NdФ/dt

where;

  • N is the number of turns of the coil
  • dФ is the change in flux
  • dt is the change in time

emf = N(BA)/t

where;

  • B is the magnetic field strength
  • A is the area of the coil
  • t is the time of motion

A = πr²

where;

  • r is the radius of the coil = 15 cm = 0.15 m

A = π(0.15)²

A = 0.071 m²

emf = (1) x (0.17) x (0.071) / 0.15

emf = 0.0805 V

emf = 80.5 mV

Learn more about induced emf here: https://brainly.com/question/17329842

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