The molecular formula of a molar mass of 127g/ mol is C9H18.
Let us assume 100g of an unknown compound.
Thus there is 37.83% × 100g/ 12.011 g[tex]mol^{-1}[/tex] concerning carbon . i.e., 3.15. mol. C
In the same manner 6.35% × 100 / 1.00794 concerning hydrogen i.e., 6.29 mol. H
Thus the empirical formula, the simplest whole number ratio that defines constituent elements is a species as CH2.
Now the molecular formula is always a whole number multiple of the empirical formula:
Empirical formula × n = molecular formula
So
( 12.011 + 2× 1.00794) ×n = 127
14.02688 × n = 127
n = 9
So the molecular formula = 9 × CH2
= C9H18
Therefore the molecular formula is C9H18.
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