Answer :

The mass of aluminum that would absorb 250kJ when melted at its melting point is 630.3g

It is given that the molar enthalpy of fusion is 396.6J and the amount of heat that would be absorbed is 250kJ. Let the mass of Aluminum should be absorbed be x. Then, it should be noted that,

1g of Aluminum can absorb 396.6 J. Then x grams of Aluminum could absorb 250kJ. Hence x could be found as,

1g of Aluminum can absorb 396.6 J

x g of Aluminum can absorb 250kJ. Therefore,

x. = 250000/396.6

x = 630.3 g

Therefore the mass of aluminum that would absorb 250000J of heat would be equal to 630.3 g

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