Let's use Probability mass function:
[tex]P(X)=\frac{1}{\sigma\sqrt[]{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^{^2}}}[/tex]Where:
[tex]\begin{gathered} \sigma=\text{ Standard deviation = 3.6} \\ \mu=\operatorname{mean}=28.4 \end{gathered}[/tex][tex]P(X)=(0,22.3)[/tex]