Answer :
Given:
The radius of the coil, r=7 cm=0.07 cm
The number of turns, N=40
The field passing through the coil, B=0.900 T
The time interval, t=0.200 s
To find:
The induced emf.
Explanation:
The emf induced is given by the equation,
[tex]\begin{gathered} E=NA\frac{B}{t} \\ =\frac{N\pi r^2B}{t} \end{gathered}[/tex]Where A is the cross-sectional area.
On substituting the known values,
[tex]\begin{gathered} E=\frac{40\times\pi\times0.07^2\times0.900}{0.2} \\ 2.77\text{ V} \end{gathered}[/tex]Final answer:
Thus the emf generated in the wire is 2.77 V
