Let's solve the equation:
[tex]\begin{gathered} \frac{1}{6}d+\frac{2}{3}=\frac{1}{4}(d-2) \\ \frac{1}{6}d+\frac{2}{3}=\frac{1}{4}d-\frac{2}{4} \\ \frac{1}{6}d-\frac{1}{4}d=-\frac{2}{3}-\frac{2}{4} \\ \frac{4d-6d}{24}=\frac{-8-6}{12} \\ -\frac{2}{24}d=-\frac{14}{12} \\ -\frac{1}{12}d=-\frac{7}{6} \\ d=\frac{-\frac{7}{6}}{-\frac{1}{12}} \\ d=\frac{(12)(7)}{6} \\ d=14 \end{gathered}[/tex]Therefore d=14