Answer :

a)

[tex]\begin{gathered} \lim _{x\to2^-}f(x)=3 \\ _{\text{ }}False \end{gathered}[/tex]

b)

[tex]\begin{gathered} \lim _{x\to2^+}f(x)=0 \\ _{\text{ }}False \end{gathered}[/tex]

c)

[tex]\begin{gathered} \lim _{x\to2^-}f(x)=\lim _{x\to2^+}f(x) \\ _{\text{ }}False \end{gathered}[/tex]

d)

[tex]\begin{gathered} \lim _{x\to2}f(x)_{\text{ }}exists \\ _{\text{ }}False \end{gathered}[/tex]

e)

[tex]\begin{gathered} \lim _{x\to4}f(x)_{\text{ }}exists;_{\text{ }}True \\ _{\text{ }}since \\ \lim _{x\to4^-}f(x)=3_{\text{ }} \\ \lim _{x\to4^+}f(x)=3_{\text{ }} \end{gathered}[/tex]

f)

[tex]\begin{gathered} \lim _{x\to4}f(x)=f(4) \\ _{\text{ }}False \\ f(4)=-1 \end{gathered}[/tex]

g) f is continuous at x = 4:

[tex]\begin{gathered} _{\text{ }}false \\ \lim _{x\to4}f(x)\ne f(4) \end{gathered}[/tex]

h) f is continuous at x = 0

[tex]_{\text{ }}True[/tex]

i)

[tex]\begin{gathered} \lim _{x\to3}f(x)=\lim _{x\to5}f(x)=3 \\ True_{\text{ }} \end{gathered}[/tex]

j) f is continuous at x = 2?

False