Answer :

Numerical Evaluation of Functions

We are given the height h as a function of time t.

h(t)=250+20t

We will evaluate the function for the times provided in the table, that is:

For t=0:

h(0)=250+20(0)

h(0)=250+0=250 feet

For t=1:

h(1)=250+20(1)

h(1)=250+20=270 feet

For t=1.5:

h(1.5)=250+20(1.5)

h(1.5)=250+30=280 feet

For t=2:

h(2)=250+20(2)

h(2)=250+40=290 feet

For t=3:

h(3)=250+20(3)

h(3)=250+60=310 feet

For t=4:

h(4)=250+20(4)

h(4)=250+80=330 feet

For t=5:

h(5)=250+20(5)

h(5)=250+100=350 feet

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