We have got a transversal line here in this question so that means that the following must be true.
[tex]\begin{gathered} (7y-23)=(23x-16) \\ (8x-21)=180-(7y-23)=-7y+203 \end{gathered}[/tex]
We have two equations and two unknowns in our hands.
[tex]\begin{gathered} 7y-23x=7 \\ 7y+8x=224 \end{gathered}[/tex]
Subtracting the first equation from the second gives us.
[tex]21x=217\Rightarrow x=\frac{217}{21}=\frac{31}{3}[/tex]
We have x now y can easily be found.
[tex]7y+8(\frac{31}{3})=224\Rightarrow7y+\frac{248}{3}=224\Rightarrow7y=224-\frac{248}{3}=\frac{424}{3}\Rightarrow y=\frac{424}{21}[/tex]
There you have it! this is the answer.
