Given:
[tex]z_1=-1.98\text{ and }z_2=1.98[/tex]
Required:
We need to find the area between z1 and z2.
Explanation:
We need to find P(-1.98[tex]We\text{ know that }P(-1.98By using the z-table, we get
[tex]P(Z<1.98)=0.97615[/tex][tex]P(Z<-1.98)=0.023852[/tex][tex]Substitute\text{ }P(Z\lt1.98)=0.976,15\text{ and }P(Z<-1.98)=0.023852\text{ in the equation.}[/tex]
[tex]P(-1.98
Final answer:
The area between the given values is 0.9523.
