Answered

Determine the volume (mL) required to prepare each of the following. 665 mL of a 0.350 M MgCl2 solution using a 4.00 M MgCl2 solution.



Answer :

To answer this question we have to use the rule of dilutions:

[tex]V1\cdot C1=V2\cdot C2[/tex]

Where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume and C2 is the final concentration. In this case we need to find V1.

Solve the equation for V1 and replace C1 for 4.00M, V2 for 665mL and C2 for 0.350M

[tex]\begin{gathered} V1=\frac{V2\cdot C2}{C1} \\ V1=\frac{665mL\cdot0.350M}{4.00M}=58.2mL \end{gathered}[/tex]

It means that the volume required is 58.2mL.

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