The parabola function is given by,
[tex]k(x)=(x-6)^2[/tex]We need to find two points on the parabola (other than vertex and x-intercepts).
Let's take a point x = 1 and find the corresponding y value:
[tex]\begin{gathered} k(x)=(x-6)^2 \\ y=(x-6)^2 \\ y=(1-6)^2 \\ y=(-5)^2 \\ y=25 \end{gathered}[/tex]So, the point is (1, 25)
Now, let's take another random x value of x = 2,
So, the corresponding y value is:
[tex]\begin{gathered} k(x)=(x-6)^2 \\ y=(x-6)^2 \\ y=(2-6)^2 \\ y=(-4)^2 \\ y=16 \end{gathered}[/tex]The other point is (2, 16)
Answer(s)[tex]\begin{gathered} (1,25) \\ (2,16) \end{gathered}[/tex]