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If some students Are you playing tug-of-war and 10 newtons of force is used in the right side and 5 N are used on the left side what is the final force placed on the rope



Answer :

The value of force acting on the right side is,

[tex]F_r=10\text{ N}[/tex]

The value of force on the left side is,

[tex]F_l=5\text{ N}[/tex]

Net force acting on the rope is,

[tex]\begin{gathered} F_{net}=F_r-F_l \\ F_{net}=10-5 \\ F_{net}=5\text{ N} \end{gathered}[/tex]

Thus, the net force acting on the rope is 5 N and is acting on the right side of the rope.

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