Answer :
A.
Let take the x-intercept and the y-intercept.
• From the graph, the x-intercept (x-axis cutting point) is >>>
[tex](x_1,y_1)=(1,0)[/tex]• The y-intercept (y-axis cutting point) is >>>
[tex](x_2,y_2)=(0,-1)[/tex]Now, let's find the point slope and slope intercept form of the line.
B.Point Slope Form
[tex]y-y_1=m(x-x_1)[/tex]Where m is given by the formula,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]So, let's substitute the the points and find the point slope form:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-0=\frac{-1-0}{0-1}(x-1) \\ y-0=\frac{-1}{-1}(x-1) \\ y-0=1(x-1) \end{gathered}[/tex]Thus, the point-slope form is
[tex]y-0=1(x-1)[/tex]C.The slope intercept form is given by
[tex]y=mx+b[/tex]Where
m is the slope and b is the y-intercept
Just re-arranging the point slope form will give us the slope intercept form. Shown below:
[tex]\begin{gathered} y-0=1(x-1) \\ y=1(x-1) \\ y=x-1 \end{gathered}[/tex]The slope intercept form is
[tex]y=x-1[/tex]