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Tommy throws a ball from the balcony of his apartment down to the street. The height of the ball, in meters, is modeled by the function shown in the graph. What's the average rate of change of the height of the ball, in meters per second, while it's in the air?Question options:A) 2∕3B) –2∕3C) –3∕2D) 3∕2

Tommy throws a ball from the balcony of his apartment down to the street The height of the ball in meters is modeled by the function shown in the graph Whats th class=


Answer :

Solution

The average rate of change of the height of the ball is given by

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here,

[tex]\begin{gathered} a=0 \\ b=10 \\ f(a)=f(0)=15 \\ f(b)=f(10)=0 \end{gathered}[/tex][tex]\begin{gathered} AverageRate=\frac{f(b)-f(a)}{b-a} \\ AverageRate=\frac{0-15}{10-0} \\ AverageRate=\frac{-15}{10} \\ AverageRate=-\frac{3}{2} \end{gathered}[/tex]

The average rate is -3/2

Option C

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