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Given:• ARST• RS = 14 in• ST = 10 in• TR= 16 inPlace the interior angles of ARST in order fromsmallest to largest.= ZR=ZS= ZT

Given ARST RS 14 in ST 10 in TR 16 inPlace the interior angles of ARST in order fromsmallest to largest ZRZS ZT class=


Answer :

KurdishPotato

Answer:

R < T < S

Step-by-step explanation:

The side lengths are proportional to the angle across to them.

The biggest angle is the angle that sees the longest side length

so we can order the angles from smallest to largest as follows:

R < T < S

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