an arrow is launched upward with a velocity of 256 feet per second from the top of a 85-foot building. what is the maximum height attained by the arrow?



Answer :

The maximum height attained by the arrow is 1109 ft.

As arrow rises to its maximum height, its velocity decreases from 256 ft/s to 0 ft/s at the rate of 32 ft/s each second. Use the following equation to determine the distance it rises.

vf^2 = vi^2 + 2 * a * d, vf = 0, a = -32

0 = 256^2 + 2 * -32 * d

64 * d = 65,536

d = 65,536 ÷ 64 = 1024 ft

Maximum height = 85 + 1024 = 1109 ft.

Distance is defined as an object's total movement without regard for direction. Distance can be defined as how much ground an object has covered regardless of its starting or ending point.

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