a square of perimeter 20 is inscribed in a square of perimeter 28. what is the greatest distance between a vertex of the inner square and a vertex of the outer square?



Answer :

Greatest distance between a vertex of the inner square and a vertex of the outer square is 4cm

What is a Square?

Square: Square is a regular quadrilateral, which has all the four sides of equal length and all four angles are also equal. The angles of the square are at right-angle or equal to 90-degrees. Also, the diagonals of the square are equal and bisect each other at 90 degrees

Perimeter of square₁, s₁=20

side of the square, a₁

4a₁=20

a₁=5

Perimeter of square₂, s₂=28

side of square, a₂

4a₂=28

a₂=7

So, a square with side 5 is inscribed in the square of side 7

By Pythagoras Theorem a² +b²=25 and a +b=7 (check the image)

we know that (a−b)²=2(a²+b²)−(a+ b)²

                       (a−b)²=2(25)-(7)²

                       (a−b)²=50-49=1

                       (a−b) =1 and a +b=7

a- b=1

a=1+b

substitute in a+ b=7

(1+b)+b=7

1+ 2b=7

2b=7-1

2b=6

b=3 and a=1+b=4

a=4cm and b=3cm is the distance of vertex of inner square to the vertex of outer square

Greatest distance between a vertex of the inner square and a vertex of the outer square is 4cm

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