a circle has an initial radius of 50 ft when the radius begins decreasing at a rate of 2 ft/min. what is the rate of change of the area at the instant the radius is 10 ft?



Answer :

The rate of change of the area at the instant the radius is 10 ft is 376.99 ft² / min.

The rate of change describes how one quantity changes in relation to the change in another quantity.

If a circle has an initial radius of 50 ft and decreases at a rate of 2 ft/min, then the time it took the radius to become 10 ft is 20 min.

r = r₀ - (rate)(time)

10 ft = 50 ft - (2 ft/min)(time)

(2 ft/min)(time) = 40 ft

time = 20 min

Solve the rate of change in area by dividing the change in area after time = 20 min.

rate of change = change in area / change in time

rate of change = A(r = 50) - A(r = 10) / 20 min

rate of change = π(50² - 10²) / 20 mins

rate of change = 376.99 ft² / min

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