Answer :
The probability of both balls being red is 2/7
Given that there are four red balls and three green balls in a bag and two of the balls are out of the bag without replacement.
We must find the probability that both balls are red.
Let us consider,
Probability of drawing a red ball = 4 red balls / 7 total balls
1st draw is (4/7)
None are replaced, (put back in the bag) so now there are 3 red balls in a bag of 6 total balls.
2nd draw is 3/6 = (1/2)
Multiply the probabilities together to find the chance of drawing red 2 times in a row.
= (4/7) * (1/2)
= 2/7
Hence, the probability that both balls are red is 2/7
Learn more about without replacement here
https://brainly.com/question/26063748
#SPJ4
