to go to sleep, oliver counted by $6$s starting from $15$. thus the first few numbers he named were $15,21,27,33,\ldots~.$the last number he named before he fell asleep was $363$. how many numbers did oliver name?



Answer :

The numbers that Oliver named are 59 in total.

If he named 1 number, the last number that he called would be 15

If he named 2 numbers, still the last number that he called would be 15 + 6 = 21

If he named 3 numbers, the last number that he called would be 15 + 6 + 6 = 27

If he named 4 numbers, the last number that he called would be 15 + 6 + 6 + 6  which is  15 + 6(4 - 1)

So, if he named n numbers, the last number that he named would be  15 + 6(n - 1)

According to the data given in the question, the last number he called was 363.

So, we can say,

363  =  15 + 6(n - 1), Subtract  15 on both sides.

348  =  6(n - 1), Divide both sides with 6.

58  =  n - 1, now, Add  1  to both sides,

we get.,

59  =  n

Hence, Oliver has named 59 numbers.

Learn more about Arithmetic progression:

https://brainly.com/question/24191546

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