In 100 individuals of rodents, 84 rodents are dominant are brown colored while recessive 16 rodents are white colored. Out of 84 dominant brown 49 rodents are found to be heterozygous dominant brown-colored rodents.
We can calculate this by taking the,
Brown = BB, Bb.( Dominant )
White = bb. ( Recessive )
BB+Bb = 84
bb = 16
Allelic frequency of b = 16/100 + (½ x 84/100)
b = 0.16 + 0.42
b = 0.58
Hence, B = 1 - 0.58 =0.42
Heterozygous Bb = 2pq
= 2 x 0.42 x 0.58
= 0.4872
No. of species(heterozygous) = 2pq x 100
= 0.4872 x 100
= 48.72
≈ 49
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