in a species of rodent, white coat color is recessive to the dominant brown color. in a population of 100 individuals, 16 are white and 84 are brown. of the 84 brown ones, how many are expected to be heterozygous (2pq)?



Answer :

In 100 individuals of rodents, 84 rodents are dominant are brown colored while recessive 16 rodents are white colored. Out of 84 dominant brown 49 rodents are found to be heterozygous dominant brown-colored rodents.

We can calculate this by taking the,

Brown = BB, Bb.( Dominant )

White = bb.  ( Recessive  )

BB+Bb = 84

bb = 16

Allelic frequency of b = 16/100 + (½ x 84/100)

b = 0.16 + 0.42

b = 0.58

Hence, B = 1 - 0.58 =0.42

Heterozygous Bb = 2pq

                            = 2 x 0.42 x 0.58

                            = 0.4872

No. of species(heterozygous) = 2pq x 100

                       = 0.4872 x 100

                       = 48.72

                         ≈ 49

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