a volleyball is spiked so that its incoming velocity of 2.75 m/s is changed to an outgoing velocity of -11.6 m/s. the mass of the volleyball is 0.350 kg. what is the magnitude of the impulse that the player applies to the ball?



Answer :

The magnitude of the impulse that the player applies to the ball is 5.0225 NSec.

Impulse in Physics is a time period this is used to explain or quantify the impact of force performed through the years to exchange the momentum of an object.

Impulse is the indispensable of a pressure, F, over the time c language, t, for which it acts. seeing that pressure is a vector quantity, the impulse is also a vector quantity. The impulse carried out to an object produces an equivalent vector alternate in its linear momentum, also in the resultant direction.

Acceleration = change in velocity

                      = final velocity - initial velocity

                      = -11.6 - ( 2.75)

      T                = -14.35

F = ma

  = 0.350 × -14.35

  = 5.0225 N

impulse = force × time

let time = 1 sec

Therefore, impulse = 5.0225 N × 1 Sec

                                  = 5.0225 Nsec

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