Answer :
The total heat required is 15.83kJ.
Solution:
Mass m = 10 g
The initial temperature of ethyl alcohol = -180.3 deg C
Melting point of ethyl alcohol= -117.3 deg C
Specific heat of ethyl alcohol (solid ) = 0.971 J/g deg C
The heat is required to increase the temperature up to the melting point
Q1 = mC delta T
Q1 = 10 g X 0.971 J/g deg C X (-117.3 degC - (-180.3degC))
Q1 = 611.73 J
The heat required to melt the ethyl alcohol (at a constant temperature)
Q2 =m X[tex]H_{fus}[/tex]
Q2 =10g X 218J/g
Q2 =2180 J
boiling point of ethyl alcohol = 78.3 deg C
melting point =-117.3 deg C
Specific heat of ethyl alcohol (liquid) = 2.30 J/g deg C
The heat is required to increase the temperature up to the boiling point
Q3 = mC delta T
Q3 = 10 g X 2.30 J/g deg C X (78.3 deg C - (-117.3 deg C))
Q3 = 4498.8 J
The heat required to convert liquid ethyl alcohol into vapor (at constant temperature)
Q4 =m X Hvap
Q4 =10g X854 J/g
Q4 =8540 J
The heat is required to increase the temperature up to the boiling point
Total Heat required = Q1 +Q2 +Q3+Q4
=611.73 J+2180 J+4498.8 J+8540 J
Total Heat required=15830.53 J= 15.83kJ
The energy required to change the temperature of 1 gram of hydrogen by 1 degree is basically defined by the specific heat of the water. The amount of energy is 4.184 J. The heat required to turn 25 grams of water into steam is 56425 joules or 13500 calories. A related example shows how the energy is calculated as water changes from solid ice to vapor.
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