Answer :
The ball to its rebound velocity is [tex]\sqrt{2}[/tex].
Solution:
H = initial hight
[tex](\frac{h}{2} )\\[/tex] = final hight
if VS and VR be striking and the rebound velocity of the ball respectively them
[tex](\frac{V_{r} }{V_{s} } ) =\sqrt{\frac{h_{12} }{h} } = \sqrt{\frac{1}{2} }[/tex]
[tex](\frac{V_{s} }{V_{r} } ) = \sqrt{2}[/tex]
Rebound means bounce in the air after hitting something hard. So rebound speed is the speed after a rebound. When bouncing, the object immediately changes speed from below. It is calculated by dividing the total number of defensive rebounds generated by a player or team by the total number of available rebounds. Multiply the result by 100 to get the percentage.
When you open the can and let the ball out more air begins to push inside the ball. As the ball ages, a small amount of air will begin to leak out minimizing internal pressure. This reduces the amount of air pushing inside the ball when it hits the ground, reducing impact. The magnitude of the parabolic velocity just before the ball hits the ground is 26.3 m/s, which is greater than the straight-falling velocity of the ball, which is 17.1 m/s.
Learn more about Rebound velocity here:-https://brainly.com/question/28155046
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