a coin is placed on a disk that is rotating at 2rev/s. if the coefficient of static friction between the coin and the disc is 0.6 what is the maximum distance from the center of the disc that the coin can be placed without it slipping off?



Answer :

The maximum distance from the center of the disc where the coin can be placed without it slipping off is 3.7 cm.

Solution:

w = (2x21) rad/s

= (2 * 2π)  rad/s

12.566 rad/s

FBD of Coin in the frame of disk

fs                N      

<--------------·-----------------> radial force (man)

for not being slip

= [tex]F_{s}[/tex] ≥ man

= [tex]M_{S} mg[/tex]  ≥ [tex]mw^{2} r[/tex]

= 0.6 * 9.8 ≥  (12.566)²r

= r ≥  0.037

rmax = 0.037 m

= 3.7cm

The coefficient of static friction is the ratio of the maximum static frictional force to the normal force between contact surfaces before they start moving. The static friction coefficient between two materials is considered a material constant. We present experiments showing that the ratio of shear force to the normal force required to move the contact body can be systematically varied by controllable changes in the external load configuration. Static friction is the force that hinders the motion of an object moving along a path. This friction occurs when two pieces of fabric slide over each other.

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