A red star and a blue star both have the same radius and are at the same distance from the earth. How does their observed brightness compare?.



Answer :

The star in blue. The power emitted by an object of area A and temperature T is P = s AT, according to the Stefan-Boltzmann Law. The blue star is hotter than the red star while having the same area as it. This implies that the blue star is hotter and emits more radiation. The blue star therefore has a higher absolute magnitude. Their apparent magnitudes are directly proportional to their absolute magnitudes if the two stars are at the same distance from Earth.

What is Stefan- Boltzmann Law?

The Stefan-Boltzmann law states that a surface's overall radiant heat output is inversely correlated with its absolute temperature.

the idea that the energy emitted by a black body per unit area per second at a certain temperature (T) is precisely proportional to T4. The Stefan constant, which has the value of 5.670400 10-8 Wm-2 K-4, is the proportionality constant. Additional name: Stefan-Boltzmann law

To know more about Stefan Boltzmann constant you may visit the link which is mentioned below:

https://brainly.com/question/13339566

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