Answer :
The energy kept in the capacitor when the potential difference becomes double is four times the initial kept energy,
The energy kept in the capacitor when the charge on each plate forms double is four times the initially stored energy.
Potential Difference :
The final potential difference is V₂=2V₁.
For the potential difference is doubled:
The formula of the energy kept in a capacitor can be defined by U₁=12CV₁₂
Then, U₁ describe the energy kept in a capacitor,
C define the capacitance and
V₁ is the potential difference.
Also , when the value of potential difference changes then the formula to calculate the energy kept in the same capacitor is presented by U₂=12CV₂₂
Here, U₂ defines the final energy kept in the capacitor after the potential change.
Commute all the known values in the above formula.
U₂=12(C)(2V₁)₂=4[12(C)(V₁)₂]=4U₁
For the charge on each plate is doubled:
The final charge on each plate can be represented as Q₂=2Q₁.The formula of the energy stored in a capacitor can be represented by, U₁=Q₁22C
Also , U₁ defines the energy kept in a capacitor, C describes the capacitance and Q₁ is the initial charge on the plate.
Likewise , when the value of charge on each plate changes then the formula to calculate the energy kept in the same capacitor is defined by,U₂=Q₂22C
Then , U₂ defines the final energy kept in the capacitor after the charge on each plate changes.
Computing all the known values in the above formula.
U₂=(2Q₁)22C=4(Q₁22C)=4U₁
Hence , the energy kept in the capacitor when the potential difference becomes double is four times the initial kept energy, and the energy kept in the capacitor when the charge on each plate becomes double is four times the initially kept energy..
To learn more about potential difference,
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