a car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 50 ft/s2. what is the distance (in ft) traveled before the car comes to a stop? (round your answer to one decimal place.)



Answer :

The distance covered by the car as it comes to rest is 13 m.

To calculate the distance covered before the car come to stop, we use the formula below.

Formula:

v² = u²+2as............... Equation 1

Where:s = distance covered by the car

v = final velocity

u = initial velocity

a = acceleration of the car

make s the subject of the equations

= (v²-u²)/2a........................Equation 2

From the question,

Given:

v = 50 mi/h = (50×0.447) = 22.35 m/su = 0

m/sa = 50 ft/s² = (50×0.3048)

= 15.24 m/s²

Substitute these values into equation

2s = (22.35²-0²)/(2×15.24)s

13m

Hence, the distance covered by the car as it comes to rest is 13 m.

Learn more about distance here: 

brainly.com/question/17273444

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