what minimum speed is required for the ball to clear the 0.90 m high net about 15.0 m from the server if the ball is hit from a height of 2.50 m?



Answer :

The velocity in the x direction is 26 m/s minimum horizontal speed.

Were asked to find the speed in the x (horizontal) direction which can be acquired from

x = vxt or vx = x/t.

We know x (15.4 m) but we need to find t.

We can find how long it takes for gravity to force the ball down from the initial height (tennis racket) to the final height (top of net) from y = yo + vot + 1/2 at2.

We'll choose y to be positive up.

The initial height yo = 2.6 m, final height y = 0.90 m, the initial velocity in the y direction is zero

vo = 0, and

a = -g (since y is positive up, gravity is downward and negative,

-g = -9.8 m/s2).

We have:0.90m = 2.6 m - 4.9 m/s2 * t2 4.9 m/s2 * t2

= 1.7 mt = ± [ 1.7 m / 4.9 m/s2 ]1/2t

= ± 0.6 s (choose + s)

Therefore, The velocity in the x direction: vx = 15.4 m / 0.6 s = 26 m/s minimum horizontal speed.

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