Answer :
Energy is stored in the electric field between the tubes is 5.85 x 10-11 J.
What is electric field?
Any charge results in an electric field being connected to a specific spot in space. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the magnitude and direction of the electric field. Without any precise information of what created the field, knowing the value of the electric field at a certain location is sufficient to predict what would happen to nearby electric charges.
We have inner tubes.
A1 = \pi ro2 = (3.14) [(0.03 m) / 2] 2
A1 = (3.14) (0.000225 m2) (0.000225 m2)
A1 = 0.0007065 m2
We have outer tubes.
A2 = \pi ri2 = (3.14) (3.14) [(0.04 m) / 2] 2
A2 = (3.14) (0.0004 m2) (0.0004 m2)
A2 = 0.001256 m2
The conducting tubes' total area is provided by -
A = (0.0007065 m2) + (0.001256 m2) (0.001256 m2)
A = 0.0019625 m2
We have a formula that yields
(8.85 x 10-12 C2/Nm2) (0.0019625 m2)/d = C = varepsilon0 A (0.3 m)
C = 5.78 x 10-14 F
The energy stored in the electric field between the tubes when these are coupled to a 45 volt battery is provided as:
U = (1/2) C V2 = (0.5) (5.78 x 10-14 F) (45 V)
U = 5852.2 x 10-14 J
U = 5.85 x 10-11 J
Learn more about electric field from given link
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