a circular loop of radius 12.0 cm is placed in a uniform magnetic field. (a) if the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 8.00 3 1023 t ? m2, what is the strength of the magnetic field?

A measurement of the total magnetic field that traverses a specific area is called magnetic flux. . The precise area selected will determine how magnetic flux is measured. The region can be any size and oriented in relation to the magnetic field as desired.

Every field line travelling across the specified area generates some magnetic flux, according to the field-line representation of a magnetic field. Another crucial factor is the angle at which the field line meets the region. Only a small portion of the field from a field line that glances through will be added to the magnetic flux. We only take into account the magnetic field vector component that is normal to our test region when computing the magnetic flux.

The magnetic flux is

Phi = B A costheta=BAcos

if we choose a basic flat surface with area AAA as our test area and an angle thetatheta between the normal to the surface and a magnetic field vector (magnitude BBB).

The following expression represents the magnetic flux through the loop in the magnetic field:

Ф=BACosФ

Here, B is the magnetic field's intensity, A is the loop's cross-sectional area, and is the angle between the magnetic field and the plane of the loop's normal.

For B, rewrite the equation.

B= Ф/AcosФ

The formula for the circular loop's surface area is,

A= π[tex]r^{2}[/tex]

Here, r denotes the loop's radius.

For r in, use 12 cm instead.

Replace with, with A, and with in.

A= 4052 x [tex]10^{-2}[/tex] [tex]m^{2}[/tex]

Consequently, the magnetic field's strength is.

B= 0.177 T

Learn more about magnetic flux from given link

https://brainly.com/question/14411049

#SPJ4