what centripetal force is needed to keep a 2 kg sack of flour moving at a constant speed of 4 m/s in a circle having a radius of (a) 4 meters (b) 8 meters?



Answer :

Centripetal force needed to keep  the 2 kg sack of flour (a) in a circle of radius 4 meters is 8 N and (b) in a circle of radius 8 meters is 4 N.

What is centripetal force?

Centripetal force can be defined as a necessary force acting of a body moving in circular or curved path in the direction of inwards towards a fixed point. Due to having both magnitude and direction, it is a vector quantity. SI unit of centripetal force is Newton (N).

We know that.

centripetal force = [tex]\frac{mv^{2} }{r}[/tex]

Where,

m = mass of the moving object.

v = speed of the moving object.

r = radius of the circular path.

Given,

Mass of the sack of flour = m= 2 kg.

Speed of the moving object = v = 4 m/s.

Now for condition (a),

When, radius of the circular path = r = 4 meter.

Required centripetal force =  [tex]\frac{mv^{2} }{r}[/tex] = [tex]\frac{2*4*4}{4}[/tex] N = 8 N.

And, for condition (b),

When, radius of the circular path = r = 8 meter.

Required centripetal force =  [tex]\frac{mv^{2} }{r}[/tex] = [tex]\frac{2*4*4}{8}[/tex] N =  4 N.

So, required centripetal force for conditions (a) and (b) respectively 8N and 4 N.

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