a hockey puck slides off the edge of a table with an initial velocity of 28.8 m/s and experiences no air resistance. the height of the tabletop above the ground is 2.00 m. what is the angle below the horizontal of the velocity of the puck just before it hits the ground?



Answer :

The puck's velocity at the moment it touches the ground is 12.6° below horizontal.

What is velocity?

The speed and direction of a point's motion are described by the idea of velocity. The pace at which the point is traveling along its path is known as the magnitude of the velocity (sometimes referred to as the speed).

The hockey puck moves with a constant horizontal velocity since there are no forces acting in this direction.

Instead, the vertical velocity alters due to the existence of acceleration caused by gravity:

[tex]V_{y}[/tex](t) =  [tex]V_{y_{0}}[/tex] -gt (1)

Here,

[tex]V_{y_{0}}[/tex] = 0 (initial vertical velocity)

g is the gravitational acceleration

t is the time

The time it takes for a hockey puck to fall from a height of h=2.00 m is determined by

h = 1/2 gt²

t = [tex]\sqrt\frac{2h}{g}}[/tex]

= [tex]\sqrt{2\times \frac{2.00}{9.8}[/tex] m/s²

= 0.408s

Adding t to (1) allows us to get the final vertical velocity.

[tex]V_{y}[/tex] = -(9.8 m/s²) (0.408 s)

= -3.9984m/s

Here, the negative sign indicates a downward-moving velocity.

We can compute the angle with respect to the horizontal now that we have both components of the velocity:

v = gt

v = [tex]\sqrt{2(9.8)(2)}[/tex]

= 6.26

tanθ = N/28

= 0.224

θ = 12.6

For more information on velocity refer to the link below:

https://brainly.com/question/12678874

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