the area of a square is increasing at a rate of 202020 square meters per hour. at a certain instant, the area is 494949 square meters. what is the rate of change of the perimeter of the square at that instant (in meters per hour)?



Answer :

Differentiation - The change of perimeter = dP/dt= 40/7m/h



What is differentiation?

Finding a function's derivative, or rate of change, is the process of differentiation in mathematics.

what is area?

It is the quantity, in other words, that counts the number of unit squares that cover the surface of a closed figure.

let the area of the square be "A" of sides "S"

area of the square

A = S²

differentiating with respect to "t" time

dA/dt = d(S²)/dt

= dA/dt = 2S*ds/dt

dA/dt=2S*ds/dt

=20m²/h

since we are given dA/dt=20

2Sds/dt=20

and at that instant A=49m sq.

=S²=49

since A=s²

S=√49

=±7

S=7

2SdS/dt=2*7ds/dt =20

ds/dt=20/14

=10/7

The perimeter of the square

P=4S

dP/dt =4dS/dt

=4*20/14

=4*10/7

thus the change of perimeter = dP/dt= 40/7m/h

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