y = x + 4 is the slope-intercept form of the equation of the line 3y−3x= 12
The equation of a line in slope-intercept form is y = mx + c.
Where m is the slope and c is the intercept
Given 3y−3x= 12
We will just make y the subject:
3y−3x= 12
3y = 3x+12
y = 3x+12/3
y = x + 4
Therefore, the slope-intercept form of the equation 3y−3x= 12 is y = x + 4
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