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The newly elected president needs to decide the remaining 4 spots available in the cabinet he /she is appointing. if there are 13 eligible candidates for these these positions where rank matters ,how many different ways can the members of the cabinet be disappointed?



Answer :

Given

There are 4 spots available in the cabinet he /she is appointing.

There are 13 eligible candidates for these positions where rank matters

As the rank matters, we will use permutations

So,

The number of ways can the members of the cabinet be disappointed =

[tex]^{13}P_4=17,160[/tex]

So, the answer will be: 17,160 ways

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