We will use a correction factor of 0.5. Then:
P(X<=25.5)
The normal distribution mean:
[tex]np=50\times0.56=28[/tex]The normal distribution standard:
[tex]\sqrt{np(1-p)}=\sqrt{28\times(1-0.56)}=3.5099[/tex]Then:
[tex]Z=\frac{x-\mu}{\sigma}=\frac{25.5-28}{3.5099}=-0.7122[/tex]From the normal distribution table, the probability is 0.239